Asked by Poppy
                the height , h(t) in metres of the trajectory of a football is  given by h(t) = 2+28t-4.9t^2, where t is the time in flight, in seconds . Determine the maximum height of thefootball and the time wehn the height is reached
            
            
        Answers
                    Answered by
            Jai
            
    to get this, we get the derivative of h(t) with respect to t, and equate it to zero:
h(t) = 2 + 28t - 4.9t^2
0 = 28 - 9.8t
9.8t = 28
t = 2.86 s
*note that the derivative of a function is the slope of the tangent line at the given point (in this problem, the point referred is the time, t, that we're solving). since the given equation is a parabola (concave downward), it has a maximum point, and at this point, the slope is zero (that's why we equate to zero)
hope this helps~ :)
    
h(t) = 2 + 28t - 4.9t^2
0 = 28 - 9.8t
9.8t = 28
t = 2.86 s
*note that the derivative of a function is the slope of the tangent line at the given point (in this problem, the point referred is the time, t, that we're solving). since the given equation is a parabola (concave downward), it has a maximum point, and at this point, the slope is zero (that's why we equate to zero)
hope this helps~ :)
                    Answered by
            zainab
            
    but how did you get the 28-9.8t?
    
                    Answered by
            jay gloden
            
    u dumb bruh
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.