Asked by Poppy
the height , h(t) in metres of the trajectory of a football is given by h(t) = 2+28t-4.9t^2, where t is the time in flight, in seconds . Determine the maximum height of thefootball and the time wehn the height is reached
Answers
Answered by
Jai
to get this, we get the derivative of h(t) with respect to t, and equate it to zero:
h(t) = 2 + 28t - 4.9t^2
0 = 28 - 9.8t
9.8t = 28
t = 2.86 s
*note that the derivative of a function is the slope of the tangent line at the given point (in this problem, the point referred is the time, t, that we're solving). since the given equation is a parabola (concave downward), it has a maximum point, and at this point, the slope is zero (that's why we equate to zero)
hope this helps~ :)
h(t) = 2 + 28t - 4.9t^2
0 = 28 - 9.8t
9.8t = 28
t = 2.86 s
*note that the derivative of a function is the slope of the tangent line at the given point (in this problem, the point referred is the time, t, that we're solving). since the given equation is a parabola (concave downward), it has a maximum point, and at this point, the slope is zero (that's why we equate to zero)
hope this helps~ :)
Answered by
zainab
but how did you get the 28-9.8t?
Answered by
jay gloden
u dumb bruh