Asked by Joseph
Yo-Yo man releases a yo-yo from rest and allows it to drop, as he keeps the top end of the string stationary. The mass of the yo-yo is 0.056 kg, its moment of inertia is 2.9 X 10^-5 kg X m^2 and the radius r of the axle the string wraps around is 0.0064 m. Through what height must the yo-yo fall for its linear speed to be 0.60 m/s?
Answers
Answered by
bobpursley
mgh=1/2 mv^2+1/2 *I w^2
but w=v/r
mgh=1/2 mv^2+1/2 *I*v^2/r^2
YOu know m,g, I ,r solve for v
but w=v/r
mgh=1/2 mv^2+1/2 *I*v^2/r^2
YOu know m,g, I ,r solve for v
Answered by
joe
h= 0.25
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