Asked by jay
As a rule of thumb, the power P (in horsepower)
that a ship needs can be modeled by P = d^2/3 • s^3 / c where d is the ship’s
displacement (in tons), s is the normal speed (in knots), and c is the Admiralty
coefficient. If a ship displaces 30,090 tons, has a normal speed of 22.5 knots,
and has an Admiralty coefficient of 370, how much power does it need?
that a ship needs can be modeled by P = d^2/3 • s^3 / c where d is the ship’s
displacement (in tons), s is the normal speed (in knots), and c is the Admiralty
coefficient. If a ship displaces 30,090 tons, has a normal speed of 22.5 knots,
and has an Admiralty coefficient of 370, how much power does it need?
Answers
Answered by
Henry
P = d^(2/3) + S^(3/c).
d = 30.090 tons.
s = 22.5 knots.
c = 370.
P = (30,090)^(2/3) + (22.5)^(3/370),
P = 967.42 + 1.0256 = 968.45 hp.
d = 30.090 tons.
s = 22.5 knots.
c = 370.
P = (30,090)^(2/3) + (22.5)^(3/370),
P = 967.42 + 1.0256 = 968.45 hp.
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