x^2 = 4/7
x = +/- sqrt (4/7) = +/- 2 sqrt(1/7)
= +/- (2/7) sqrt(7)
Use the sqaure root property to solve the equation.
7x^2-4=0
2 answers
7x^2-4
x^2-4=1/7
x^-2=1/7
1/x^2=1/7
[1/x]^2=1/7
1/x=1/sqrt7
x=sqrt7
x^2-4=1/7
x^-2=1/7
1/x^2=1/7
[1/x]^2=1/7
1/x=1/sqrt7
x=sqrt7
1 answer