Asked by stellar
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
sin θ cos θ − 2 sin θ = 0
sin θ cos θ − 2 sin θ = 0
Answers
Answered by
MathMate
sin θ cos θ − 2 sin θ = 0
factor out sin(θ)
sin(θ)(cos(θ)-2) = 0
Can you take it from here?
factor out sin(θ)
sin(θ)(cos(θ)-2) = 0
Can you take it from here?
Answered by
stellar
that is where i got stuck
Answered by
Steve
When a product of factors is zero, one of the factors must be zero.
So, either
sin(θ) = 0 or cos(θ)-2 = 0
sin(θ) = 0 when θ = k*pi
cos(θ)-2 = 0 when cos(θ) = 2
but cos(θ) is always less than 1. No solution here.
So, either
sin(θ) = 0 or cos(θ)-2 = 0
sin(θ) = 0 when θ = k*pi
cos(θ)-2 = 0 when cos(θ) = 2
but cos(θ) is always less than 1. No solution here.
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