Asked by Loretta
An isotope of Glopenium disintegrates according to the formula
A(t) = Ao2^-0.0345t where Ao is the initial mass of the substance and t is the time in years. If there are 2 milligrams of Glopenium now, find the number of milligrams that will be left after 35 years. Your answer should be correct to the nearest thousandth of a milligram.
A(t) = Ao2^-0.0345t where Ao is the initial mass of the substance and t is the time in years. If there are 2 milligrams of Glopenium now, find the number of milligrams that will be left after 35 years. Your answer should be correct to the nearest thousandth of a milligram.
Answers
Answered by
Steve
You have the formula, what's the problem?
A(35) = 2 * 2^-(0.0345*35)
A(35) = 2 * 2^-(0.0345*35)
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