Question
A 2.6 m long, 16 kg piece of plywood is sitting on a pair of sawhorses. The sawhorses are .3 m from the left end and .5 m in from the right end of the plywood. A 4 kg circular saw is sitting 1 m in from the left end of the plywood. How much force is each sawhorse applying? Assume the plywood is of uniform constant.
Again, I'm lost. Any help is much appreciated.
Again, I'm lost. Any help is much appreciated.
Answers
tchrwill
A 2.6 m long, 16 kg piece of plywood is sitting on a pair of sawhorses. The sawhorses are .3 m from the left end and .5 m in from the right end of the plywood. A 4 kg circular saw is sitting 1 m in from the left end of the plywood. How much force is each sawhorse applying? Assume the plywood is of uniform constant.
.............6.1538kg/m
...............\/
---------------------------------
....../\.....\/.........../\
..3m..Rl.7m.4kg...1.8m....Rr.5m
Rl and Rr are the left and right reactions respectively.
Taking the summation of moments about the left reaction, we have
-.3(6.1538).15 + 4(.7) + 2.3(6.1538)1.15 - 1.8rR.
Solve for Rr.
Take the summation of vertical forces to derive the left reaction.
......RL................Rr
.............6.1538kg/m
...............\/
---------------------------------
....../\.....\/.........../\
..3m..Rl.7m.4kg...1.8m....Rr.5m
Rl and Rr are the left and right reactions respectively.
Taking the summation of moments about the left reaction, we have
-.3(6.1538).15 + 4(.7) + 2.3(6.1538)1.15 - 1.8rR.
Solve for Rr.
Take the summation of vertical forces to derive the left reaction.
......RL................Rr