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the (OH) of ammonia solution is 4.0 x10-2 M. What is the (H3O+) of the solution?
13 years ago

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DrBob222
............NH3 + HOH ==> NH4^+ + OH^-
initial...0.040...........0........0
change......-x............x.........x
equil.......0.040-x.......x..........x

Kb = (NH4^+)(OH^-)/(NH3)
Substitute Kb, and numbers/symbols from the ICE chart and solve for x = (OH-).
Then (H^+)(OH^-) = Kw = 1E-14.
13 years ago

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