All of these follow two/three formulas.
(H+)(OH^-) = Kw = 1E-14
pH = -log(H^+)
pOH = -log(OH^-)
pH + pOH = pKw = 14.
Complete this table of values for four aqueous solutions at 25 °C.
Solution A: [H+]=0.0093M [OH-]=? pH=? pOH=?
Solution B: [H+]=?[OH-]=1.4e-6M pH=? pOH=?
Solution C: [H+]=?[OH-]=? pH=5.36 pOH=?
Solution D: [H+]=?[OH-]=? pH=? pOH=10.14
2 answers
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