This is benzoic acid; let's call it HBz
..............HBz ==> H^+ + Bz^-
initial......0.06.....0......0
change........-x.......x.....x
equil.......0.06-x.....x.....x
K + (H^+)(Bz^-)/(HBz)
Substitute and solve for (H^+).
Calculate the equilibrium concentration of H3O+ in the solution if the initial concentration of C6H5COOH is 6.0×10^-2. Kc=6.3 *10^-5
1 answer
1 answer