kw=conccH+ * concOH- where they are equal.
kw=x^2
x=sqrt kw=sqrt(2.4E-14)=1.55 E-7
pH=-log (1.55E-7)=6.81
Given that Kw for water is 2.4× 10–14 at 37 °C, compute the pH of a neutral aqueous solution at 37 °C, which is the normal human body temperature.
1 answer
1 answer