Asked by patel
a chemistry experiment calls for 30% sulfuric acid solution. if the supply room has only 50% and 20% sulfuric acid solution on hand,how much of each should be mixed to obtain 12 litres of 30% solution?
Answers
Answered by
Steve
Think of the total amounts of solute in the various concentrations. If you mix them, you get
.5x + .2(12-x) = .3(12)
.3x = 1.2
x = 4
.5x + .2(12-x) = .3(12)
.3x = 1.2
x = 4
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