Asked by Monique
A mixture containing 235 mg of Helium and 325 mg of neon has a total pressure of 453 torr. What is the partial pressure of Helium
Answers
Answered by
DrBob222
moles He = grams/molar mass
moles Ne = grams/molar mass
mole fraction He, XHe = moles He/total moles.
PHe = XHe*453
PNe = XNe*453
moles Ne = grams/molar mass
mole fraction He, XHe = moles He/total moles.
PHe = XHe*453
PNe = XNe*453
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