Require that the range (between release point and goal) equals 10.4 m. The range is
10.4 = (Vo^2/g)*sin(2*56.8).
Solve for Vo
Assume: A 78 g basketball is launched at an angle of 56.8◦ and a distance of 10.4 m from the basketball goal. The ball is released at the same height (ten feet) as the basketball goal’s height. A basketball player tries to make a long
jump-shot as described above. The acceleration of gravity is 9.8 m/s^2. What speed must the player give the ball?
Answer in units of m/s
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did you get the answer because i need it now and it's due tomorrow???
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