1/16(x)^3a + 1/2(y)^(6a)(z)^(9b)
2 answers
Factor.
= (1/16)(x^(3a) + 8y^(6a)z^(9b) )
= (1/16) [ (x^a)^3 + (2(y^(2a)^3z^(3b) )^3 )
recall A^3 + b^3 = (A+B)(A^2 + AB + B^2)
using A = x^a , B = 2y^(2a)z^(3b)
factor the last part as a sum of cubes
= (1/16) [ (x^a)^3 + (2(y^(2a)^3z^(3b) )^3 )
recall A^3 + b^3 = (A+B)(A^2 + AB + B^2)
using A = x^a , B = 2y^(2a)z^(3b)
factor the last part as a sum of cubes