Asked by Tyler
George takes off for a long jump at an angle of 28 degrees, and lands 6.9 m away. How fast was he when he jumped?
Answers
Answered by
Henry
Dh = Vo^2*sin(2A) / g = Hor. distance,
Dh = Vo^2*sin56 / 9.8 = 6.9,
0.829Vo^2 / 9.8 = 6.9,
0.0846Vo^2 = 6.9,
Vo^2 = 81.56,
Vo = 9.03m/s.
Dh = Vo^2*sin56 / 9.8 = 6.9,
0.829Vo^2 / 9.8 = 6.9,
0.0846Vo^2 = 6.9,
Vo^2 = 81.56,
Vo = 9.03m/s.
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