Asked by ZUkii
write a differential equation for the following.
a cell starts at a volume of 400m^3 and gains volume at a rate of 3m^3/s
a cell starts at a volume of 400m^3 and gains volume at a rate of 3m^3/s
Answers
Answered by
Steve
Uh, how about
v = 400 + 3t
where t is the time in seconds
You want volume in m<sup>3</sup>. Keep the units as you go along, and you can see what has to be used:
v = 400m<sup>3</sup> + 3m<sup>3</sup>/s * s
That's why you multiply by time, to change rate to volume. You can only add like units: volume.
I also assume you mean µm or something like that. Most cells don't come in meter sizes ...
v = 400 + 3t
where t is the time in seconds
You want volume in m<sup>3</sup>. Keep the units as you go along, and you can see what has to be used:
v = 400m<sup>3</sup> + 3m<sup>3</sup>/s * s
That's why you multiply by time, to change rate to volume. You can only add like units: volume.
I also assume you mean µm or something like that. Most cells don't come in meter sizes ...
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.