Take a look at the Related Questions below. The general outline for solution is:
find the slope of the tangent to the curve at any x: dy/dx
evaluate y' at the given x. That will provide the slope of the line you want.
Now you have a point and a slope. Use the point-slope form of the equation for a line.
easy peasy . . .
Find the equation of the tangent to the curve x^2+y^2=25 at (-3,4).
I'm really confused on how to get the answer, someone please help
2 answers
unknown