Asked by Anonymous
A billiard ball moving at 6.00 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 5.39 m/s, at an angle of 26.0 with respect to the original line of motion
(a) Find the velocity (magnitude and direction) of the second ball after collision
(a) Find the velocity (magnitude and direction) of the second ball after collision
Answers
Answered by
Damon
initial x momentum = 6 m
initial y momentum = 0
final x momentum = m(5.39 cos 26) + m Vx
final y momentum = m (5.39 sin 26)+ m Vy
m cancels
initial = final
solve for Vx and Vy
initial y momentum = 0
final x momentum = m(5.39 cos 26) + m Vx
final y momentum = m (5.39 sin 26)+ m Vy
m cancels
initial = final
solve for Vx and Vy
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