Asked by NONO

find the slope of the curve x^3 y^3 + y^2 = x + y at the point (1,1) and (1,-1)??
Answered by Steve
x<sup>3</sup>y<sup>3</sup> + y<sup>2</sup> = x + 1

3x<sup>2</sup>y<sup>3</sup> + 3x<sup>3</sup>y<sup>2</sup>y' = 1 + y'

At (1,1)
3 + 3y' = 1 + y'
y' = -1

At (1,-1)
-3 + 3y' = 1 + y'
y' = 2
Answered by NONO
WHAT IS THAT x3y3 + y2 = x + 1
??
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