find the slope of the curve x^3 y^3 + y^2 = x + y at the point (1,1) and (1,-1)??

Answer 1

x³y³ + y² = x + 1

3x²y³ + 3x³y²y' = 1 + y'

At (1,1)
3 + 3y' = 1 + y'
y' = -1

At (1,-1)
-3 + 3y' = 1 + y'
y' = 2

Answer 2

WHAT IS THAT x3y3 + y2 = x + 1
??