Asked by fausto
sinx=square root of 3 over 2, cosx=1 over 2 i want to find all six trigonometric functions
Answers
Answered by
Reiny
sinx = √3/2 , cosx = 1/2
the sine and cosine are both positive only in quadrant I
and I see the ratios of the 30-60-90 right-angled triangle which are 1 : √3 : 2
sinx = √3/2 , cscx = 2/√3
cosx = 1/2 , sec x = 2
tanx =√3, cotx = 1/√3
the sine and cosine are both positive only in quadrant I
and I see the ratios of the 30-60-90 right-angled triangle which are 1 : √3 : 2
sinx = √3/2 , cscx = 2/√3
cosx = 1/2 , sec x = 2
tanx =√3, cotx = 1/√3
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