Asked by Anonymous
A triangular pennant has two sides the same length. The third side is 9 in. shorter than either of the equal sides. The perimeter of the pennant is 57 in. How long is the shortest side?
Answers
Answered by
Ms. Sue
Let x = a longer side
2x + x - 9 = 57
3x = 57 + 9
3x = 66
x = 22
2x + x - 9 = 57
3x = 57 + 9
3x = 66
x = 22
Answered by
Kaylee Harmon
Let x = a longer side
2x + x - 9 = 57
3x = 57 + 9
3x = 66
x = 22
22 - 9 = 13
The shorter side is 13 inches long.
2x + x - 9 = 57
3x = 57 + 9
3x = 66
x = 22
22 - 9 = 13
The shorter side is 13 inches long.
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