Asked by mary
Have 250 mL of a 0.80 M solution of silver nitrate AgNO3 dissolved in water. how many grams of AgNO3 does the solution contain
Answers
Answered by
Steve
250 mL of 0.8M solution means there are 0.2M of AgNO<sub>3</sub>
The mole weight of AgNO<sub>3</sub> is
107.9 + 14.01 + 3*16.0 = 169.91g
You have .2M, or 33.99g
The mole weight of AgNO<sub>3</sub> is
107.9 + 14.01 + 3*16.0 = 169.91g
You have .2M, or 33.99g
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