Solve 5x^3 – 6x^2 – 4x – 8 = 0

1 answer

first try some factors of 8
after 2 attempt I found x = 2 works
so x-2 is a factor
by synthetic division ....
5x^3 – 6x^2 – 4x – 8
= (x-2)(5x^2 + 4x + 4)

now solve 5x^2 + 4x + 4 = 0
Use the formula, you will get two complex roots
Similar Questions
    1. answers icon 1 answer
  1. Combine like terms:-3x^2+2x-4x^2-9+6x-2x^2+8 Solve for x: 8x-11= -11x+18 Solve for x: -2(x-5)+7=z-8-5x Solve for x: (x-2)/5 -
    1. answers icon 8 answers
  2. Solve the indicated variable:1. Volume of a cone: solve for h: V=¨ir^2h/3 2. Temperature formula: solve for C: F=9/5C+32
    1. answers icon 1 answer
  3. Put in the correct orderSolve exponentiation. Solve multiplication and division. Solve operations within parentheses Solve
    1. answers icon 1 answer
more similar questions