determine the maximum or the minimum of
a)2x^2+12x
2 answers
2x^2+10 maybe?
2x^2+12x
= 2(x^2 + 6x)
= 2(x^2 + 6x + 9 - 90)
= 2( (x+3)^2 - 9)
= 2(x+3)^2 - 18
Minimum value of -18 when x = -3
= 2(x^2 + 6x)
= 2(x^2 + 6x + 9 - 90)
= 2( (x+3)^2 - 9)
= 2(x+3)^2 - 18
Minimum value of -18 when x = -3