A bowling ball weighing 40.0 N initially moves at a speed of 4.90 m/s. How long must a force of 54.0 N be applied to the ball to stop it?

Answer 1

The ball weighing 40N has a mass given by

F = ma
40 = 9.8m
m = 4.08kg

So, a force of 54N will produce a deceleration of 54/4.08 = -13.235 m/s^2,

v = 4.9 + at
0 = 4.9 - 13.235t
t = 4.9/13.25 = .302s