h(t)=-5t^2+17t+22
dh/dt=-10t+17 =0 at max height.
t= 10/17
h(max)=-5(10/17)^2 + 17(10/17)+22
when is h(t)=0, that is the ground.
a ball is kicked in the air from the top of a cliff. the path the ball travels is given by the equation h(t)=-5t^2+17t+22 where h(t) is the height in metres and t is the time in seconds
a) what is the maximum height that the ball reaches
b)when will the ball hit the ground
2 answers
thank you !!!