energy from gravity: mgh=mg(210sin10.3)
energy into snow: 210*mg*cos10.3+mgL
set the two energies equal, solve for L.
A skier starts from rest at the top of a hill that is inclined at 10.3° with the horizontal. The hillside is 210 m long, and the coefficient of friction between snow and skis is 0.0750. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier glide along the horizontal portion of the snow before coming to rest?
2 answers
oops, I forget mu coefficent friction.
energy in snow= 210*mu*mg*cos10.3 +mu*mgL
energy in snow= 210*mu*mg*cos10.3 +mu*mgL
1 answer