Asked by Anil
                rectangular open-topped box is made from a 9 x 16 piece of cardboard by cutting x-inch squares out of each corner and folding up the sides.
What size square should be cut out to produce a volume of 120 cubic inches??
I set it up with
120 = (16-2x)(9-2x)(x)
I get to
y = 2x^3 - 25x^2 +72x -60 and I'm stuck. Where do I go from here?
            
        What size square should be cut out to produce a volume of 120 cubic inches??
I set it up with
120 = (16-2x)(9-2x)(x)
I get to
y = 2x^3 - 25x^2 +72x -60 and I'm stuck. Where do I go from here?
Answers
                    Answered by
            tchrwill
            
    Let the corner pieces be x by x.
Then, x(16 - 2x)(9 - 2x) = 120
144x - 50x^2 + 4x^3 = 120
4x^3 - 50x^3 + 144x - 120 = 0
2x^3 - 25x^2 + 72x - 60 = 0
First derivative =
6x^2 - 50x + 72 = 0
3x^2 - 25x + 36 = 0
x = [25+/-sqrt(25^2 - 4(3)36)]/6
x = 1.851
    
Then, x(16 - 2x)(9 - 2x) = 120
144x - 50x^2 + 4x^3 = 120
4x^3 - 50x^3 + 144x - 120 = 0
2x^3 - 25x^2 + 72x - 60 = 0
First derivative =
6x^2 - 50x + 72 = 0
3x^2 - 25x + 36 = 0
x = [25+/-sqrt(25^2 - 4(3)36)]/6
x = 1.851
                    Answered by
            Anil More help
            
    I don't know calculus. I'm still in algebra.  please explain
    
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