IDENTIFY THE CONJUGATE ACID-BASE PAIR IN THE FOLLOWING REACTIONS.

A) HSO4^- + SO3^2- <---> HSO3^- + SO4^2-
B) S^2- + H20 <----> HS^- + OH^-
C) CN^- + H3O^+ <----> HCN + H2O
D) H2SE + H2O <----> HSE^- + H3O^+

User Icon for DrBob222 DrBob222 answered
13 years ago

What do you not understand about this? Look for the ion that has an H on one side and one fewer H on the other side. That's all there is to it.

User Icon for HELP IM LOST HELP IM LOST answered
13 years ago

so which one is the acid and which one is the base

User Icon for DrBob222 DrBob222 answered
13 years ago

The one with more H is the acid and the one with one fewer H is the base.

HSO4^- is the acid. SO4^2- is the base.
SO3^2- is the base; HSO3^- is the acid.

User Icon for Explain Bot Explain Bot answered
1 year ago

To identify the conjugate acid-base pairs in the given reactions, we need to understand the concept of conjugate acid-base pairs.

In a chemical reaction, an acid donates a proton (H+) to a base, and the base accepts that proton. The acid is then converted into its conjugate base, and the base is converted into its conjugate acid. The conjugate acid-base pairs always differ by the presence or absence of one proton.

Let's go through each reaction and identify the conjugate acid-base pairs:

A) HSO4^- + SO3^2- <--> HSO3^- + SO4^2-
In this reaction, HSO4^- donates a proton (H+) to SO3^2-, forming its conjugate base HSO3^-. Similarly, SO4^2- accepts the proton, forming its conjugate acid SO3^2-. Therefore, the conjugate acid-base pairs in this reaction are HSO4^-/HSO3^- and SO3^2-/SO4^2-.

B) S^2- + H2O <--> HS^- + OH^-
In this reaction, S^2- donates a proton (H+) to water (H2O), forming its conjugate acid HS^-. Simultaneously, water accepts the proton, forming its conjugate base OH^-. Therefore, the conjugate acid-base pairs in this reaction are S^2-/HS^- and H2O/OH^-.

C) CN^- + H3O^+ <--> HCN + H2O
In this reaction, CN^- donates a proton (H+) to H3O^+, forming its conjugate acid HCN. At the same time, H3O^+ accepts the proton, forming its conjugate base H2O. Therefore, the conjugate acid-base pairs in this reaction are CN^-/HCN and H3O^+/H2O.

D) H2SE + H2O <--> HSE^- + H3O^+
In this reaction, H2SE donates a proton (H+) to water (H2O), forming its conjugate acid HSE^-. Meanwhile, water accepts the proton, forming its conjugate base H3O^+. Thus, the conjugate acid-base pairs in this reaction are H2SE/HSE^- and H2O/H3O^+.

In summary, the conjugate acid-base pairs for the given reactions are:
A) HSO4^-/HSO3^- and SO3^2-/SO4^2-
B) S^2-/HS^- and H2O/OH^-
C) CN^-/HCN and H3O^+/H2O
D) H2SE/HSE^- and H2O/H3O^+