Asked by Sushmitha

solve system of equations:

y = 2x^3 - 2x^2

y = -6x^2 +30x
I know (0,0) is one point.
How do I get others?
Answered by Sushmitha
OK, I got it.
Answered by bobpursley
y=y, so set the equations equal
2x^3-2x^2=-6x^2+30x

2x^3+4x^2-30x=0
2x(x^2+2x-15)=0
2x(x-3)(x+5)=0
x=0/ x=3/x=-5
find the y for each of those three points.


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