solve system of equations:
y = 2x^3 - 2x^2
y = -6x^2 +30x
I know (0,0) is one point.
How do I get others?
2 answers
OK, I got it.
y=y, so set the equations equal
2x^3-2x^2=-6x^2+30x
2x^3+4x^2-30x=0
2x(x^2+2x-15)=0
2x(x-3)(x+5)=0
x=0/ x=3/x=-5
find the y for each of those three points.
2x^3-2x^2=-6x^2+30x
2x^3+4x^2-30x=0
2x(x^2+2x-15)=0
2x(x-3)(x+5)=0
x=0/ x=3/x=-5
find the y for each of those three points.
2 answers