the reaction CO + 2H2<----->CH3OH has a delta H -18 kJ. how will the amount of CH3OH be affected by the following.

Question

a) removing H2(g)
b) decreasing the volume of the container.

Answer 1

This is a question on Le Chatelier's Principle. Basically that principle tells us that a system in equilibrium will try to undo what we do to it. That isn't what you read in a text but it is one way to look at it.
So if we ADD H2 to the system it will try to undo that. How can it do that? By using up the added H2 of course. So the reaction will shift to the right (producing more CH3OH at the expense of H2 and CO). Increasing pressure will shift it to the side with FEWER moles. Take this information and answer the questions.