Asked by sexy
the reaction CO + 2H2<----->CH3OH has a delta H -18 kJ. how will the amount of CH3OH be affected by the following.
a) removing H2(g)
b) decreasing the volume of the container.
a) removing H2(g)
b) decreasing the volume of the container.
Answers
Answered by
DrBob222
This is a question on Le Chatelier's Principle. Basically that principle tells us that a system in equilibrium will try to undo what we do to it. That isn't what you read in a text but it is one way to look at it.
So if we ADD H2 to the system it will try to undo that. How can it do that? By using up the added H2 of course. So the reaction will shift to the right (producing more CH3OH at the expense of H2 and CO). Increasing pressure will shift it to the side with FEWER moles. Take this information and answer the questions.
So if we ADD H2 to the system it will try to undo that. How can it do that? By using up the added H2 of course. So the reaction will shift to the right (producing more CH3OH at the expense of H2 and CO). Increasing pressure will shift it to the side with FEWER moles. Take this information and answer the questions.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.