Asked by alya
a piece of wire of length 136(pai) is cut to form 8 circles. the radius of the circles differ from each other, in sequence, by 1 cm.
a) find the radius,r
b) find the number of complete circles that can be formed if the original length of the wire is 190(pai)
a) find the radius,r
b) find the number of complete circles that can be formed if the original length of the wire is 190(pai)
Answers
Answered by
drwls
How long is a "pai" ? I am not familiar with that unit of length
Answered by
alya
3.142
Answered by
Writeacher
I think you mean <i>pi</i>, right?
http://www.google.com/search?rlz=1C1GGGE_enUS379US379&gcx=c&sourceid=chrome&ie=UTF-8&q=pi
http://www.google.com/search?rlz=1C1GGGE_enUS379US379&gcx=c&sourceid=chrome&ie=UTF-8&q=pi
Answered by
alya
yup.. pi.. so i want to know how to solve it
Answered by
drwls
pi is the number but what is the dimension? Is the original wire length 136 pi centimeters?
Answered by
Reiny
I agree that you probably meant 136π for the length of the wire
let the first circle have a radius of r
then the others are
r+1, r+2 ,.. , r+7
so the circumferences would be
r(2π) + (r+1)(2π) + ... + (r+7)(2π)
= 2π[ r + r+1 + ... + r+7 ]
= 2π[ 4(r + r+7) , using (n/2)(first + last) as the sum of n terms of an AS
= 2π(8r + 28)
= 136π
2π(8r+28) = 136π
8r + 28 = 68
r = 5
check:
circumferences are
2π(5+6+...+12)
using (n/2)(first + last) as the sum of n terms of an AS
= 2π(4)(5+12) = 136π
length of wire = 136π , perfect!
b)
I assume your circles will start with a radius of 5 and increase by 1
let the number of complete circles be n, where n will have to be a whole number
2π(5 + 6 + .. (n-1) ) = 190π
5+6+... + 5+n-1 = 95
(n/2)(5 + 5+n-1) = 95
n(9+n) = 190
n^2 + 9n - 190 = 0
(n-10)(n+19) = 0
n=10 or a negative
So he will be able to form 10 complete circles.
check:
let the first circle have a radius of r
then the others are
r+1, r+2 ,.. , r+7
so the circumferences would be
r(2π) + (r+1)(2π) + ... + (r+7)(2π)
= 2π[ r + r+1 + ... + r+7 ]
= 2π[ 4(r + r+7) , using (n/2)(first + last) as the sum of n terms of an AS
= 2π(8r + 28)
= 136π
2π(8r+28) = 136π
8r + 28 = 68
r = 5
check:
circumferences are
2π(5+6+...+12)
using (n/2)(first + last) as the sum of n terms of an AS
= 2π(4)(5+12) = 136π
length of wire = 136π , perfect!
b)
I assume your circles will start with a radius of 5 and increase by 1
let the number of complete circles be n, where n will have to be a whole number
2π(5 + 6 + .. (n-1) ) = 190π
5+6+... + 5+n-1 = 95
(n/2)(5 + 5+n-1) = 95
n(9+n) = 190
n^2 + 9n - 190 = 0
(n-10)(n+19) = 0
n=10 or a negative
So he will be able to form 10 complete circles.
check:
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