Asked by Gracy
a die is rolled 7 times. find the probability of getting at least one 3.
Answers
Answered by
Reiny
so we exclude the probability of "no 3"
prob of no 3 in 7 tries = (5/6)^7
prob of your event = 1 - (5/6)^7 = .7209
prob of no 3 in 7 tries = (5/6)^7
prob of your event = 1 - (5/6)^7 = .7209
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