Asked by jordan
A developer wants to build homes on a rectangular plot of land 4 kilometers long and 3 kilometers wide. In this part of the city, regulations require a greenbelt of uniform width along two adjacent sides. The greenbelt must be 10 times the area of the development. find the width of the greenbelt.
Answers
Answered by
Damon
area of development = 3*4 = 12 km^2
greenbelt area = 120 km^2:
one end = (3+w) by w
other end = 4 by w
so
120 = 4 w + 3 w + w^2 = w^2 + 7 w
w^2 + 7 w - 120 = 0
w = [ -7 +/- sqrt (49+480) ] / 2
= [ -7 +/- 23]/2
use + root only
w = 8
greenbelt area = 120 km^2:
one end = (3+w) by w
other end = 4 by w
so
120 = 4 w + 3 w + w^2 = w^2 + 7 w
w^2 + 7 w - 120 = 0
w = [ -7 +/- sqrt (49+480) ] / 2
= [ -7 +/- 23]/2
use + root only
w = 8
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