Asked by kellie

A 1.21 kg block slides down a 25.0 m long 25.0° incline at constant velocity. How much work is done by friction?
Answered by bobpursley
work= force dot distance= mg*15.0*cos 25
Answered by Allen
Where is the 15 coming from? I thought that you may have meant 25 so I calculated 1.21*9.8*25*cos 25 and I got the answer wrong.
Answered by Kellie
Yea, I was wondering the same thing because mine is wrong too!
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