Question
A car traveling at 18 m/s accelerates at 5.5 m/s2 for 9 s. How far does the car travel during the time it is accelerating for 9 seconds?
Answers
mike
1. Change in velocity = acceleration * time = 5.5 m/s2 * 9 s = 49.5 m/s
2. Final velocity = Initial Velocity + Change in velocity = 18 + 49.5 m/s = 67.5 m/s
3. distance = (Final velocity ^ 2 - Inital velocity ^ 2) / (2 * acceleration) = (67.5 m/s * 67.5 m/s - 18 * 18) / (2 * 5.5 m/s2) = 384.75 m
2. Final velocity = Initial Velocity + Change in velocity = 18 + 49.5 m/s = 67.5 m/s
3. distance = (Final velocity ^ 2 - Inital velocity ^ 2) / (2 * acceleration) = (67.5 m/s * 67.5 m/s - 18 * 18) / (2 * 5.5 m/s2) = 384.75 m