f(x) = x^2 - 8x - 17 at x = 4
I came up with 8 ?
Find the derivative of f 0f x.
f(x) = x^2 - 8x - 17 at x = 4
4 answers
f'(x) = 2 x -8
when x = 4
f'(x) = 2*4 - 8
= 0
when x = 4
f'(x) = 2*4 - 8
= 0
You were given:
Find the derivative of f 0f x.
f(x) = x^2 - 8x - 17 at x = 4
We first find the derivative of the given function and then replace x with 4 in the derivative we will find.
I will use the power rule to find the derivative of your function.
The Power Rule: The derivative of the term a(x^n) (with respect to x), where a and n are real numbers is:
(a times n)[x^ (n - 1)].
We apply the power rule on each term of the function individually.
f(x) = x^2 - 8x - 17
The derivative of x^2 = 2x.
The derivative of 8x = 8
The derivative of any constant = 0.
So, the derivative of constant -17 = 0.
We now have the function:
f'(x) = 2x - 8
We now replace x with 4 and simplify.
f'(x) = 2(4) - 8
f'(x) = 8 - 8
f'(x) = 0
So, the derivative of the original function at x = 4 is ZERO.
Find the derivative of f 0f x.
f(x) = x^2 - 8x - 17 at x = 4
We first find the derivative of the given function and then replace x with 4 in the derivative we will find.
I will use the power rule to find the derivative of your function.
The Power Rule: The derivative of the term a(x^n) (with respect to x), where a and n are real numbers is:
(a times n)[x^ (n - 1)].
We apply the power rule on each term of the function individually.
f(x) = x^2 - 8x - 17
The derivative of x^2 = 2x.
The derivative of 8x = 8
The derivative of any constant = 0.
So, the derivative of constant -17 = 0.
We now have the function:
f'(x) = 2x - 8
We now replace x with 4 and simplify.
f'(x) = 2(4) - 8
f'(x) = 8 - 8
f'(x) = 0
So, the derivative of the original function at x = 4 is ZERO.
Thanks looks like I forgot to subtract 8
1 answer