Asked by chris
For a week acid whose ionization constant is 1.75 x 10(-5), the pH of its solution is 3.0. Determine its degree of ionization and its percent ionization.
Answers
Answered by
DrBob222
HA ==> H^+ + A^-
Ka = (H^+)A^-)/(HA)
Set up an ICE chart and solve for (HA). Then
%ion = [H^+)/(HA)]*100 = ?
degree ion = %ion/100.
Ka = (H^+)A^-)/(HA)
Set up an ICE chart and solve for (HA). Then
%ion = [H^+)/(HA)]*100 = ?
degree ion = %ion/100.
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