Asked by tori

CH2==Ch2(g) ----> CH4(g) + C (graphite)
If the decomposition begina at 10 degrees C and 50.0 atm with a gas density of 0.215 g/mL and the temperature increases by 950K, what is the final pressure of the confined gas (ignore the volume of graphite and use the van der waals equation)

Answers

Answered by DrBob222
So what's your problem? Just plug into the van der Waals equation.
Answered by tori
I don't know how to throw density into the equation.
Answered by tori
scratch that.. i really don't get any of it. formula I have is: (P + (n^2a)/V^2)(V-nb) = nRT

what I can fill in is (P + (n^2(2.25))/V^2)(V-n(.0428)) = n(.0821)(950)
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