Asked by tori
CH2==Ch2(g) ----> CH4(g) + C (graphite)
If the decomposition begina at 10 degrees C and 50.0 atm with a gas density of 0.215 g/mL and the temperature increases by 950K, what is the final pressure of the confined gas (ignore the volume of graphite and use the van der waals equation)
If the decomposition begina at 10 degrees C and 50.0 atm with a gas density of 0.215 g/mL and the temperature increases by 950K, what is the final pressure of the confined gas (ignore the volume of graphite and use the van der waals equation)
Answers
Answered by
DrBob222
So what's your problem? Just plug into the van der Waals equation.
Answered by
tori
I don't know how to throw density into the equation.
Answered by
tori
scratch that.. i really don't get any of it. formula I have is: (P + (n^2a)/V^2)(V-nb) = nRT
what I can fill in is (P + (n^2(2.25))/V^2)(V-n(.0428)) = n(.0821)(950)
what I can fill in is (P + (n^2(2.25))/V^2)(V-n(.0428)) = n(.0821)(950)
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