Asked by Shellu
Calculate [H3O+] and [OH-] in 0.22M KOH(aq)
Answers
Answered by
DrBob222
KOH is a strong base; therefore, (OH^-) = 0.22M
Then (H^+)(OH^-) = Kw = 1E-14. Solve for (H^+).
Then (H^+)(OH^-) = Kw = 1E-14. Solve for (H^+).
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