Asked by Courtney
Please check my answer: I think it's correct?
1.Find polar form of (-3,2)
r=sqrt of (-3)^2 + 2^2)=sqrt (13) = 3.61
tan^-1(2/-3) = 33.79
180-33.79 = 146.31degrees
polar points are (sqrt13,146.31degrees)
2. Rectangular form of (3,112degrees)
3cos112= (-1.12)
3sin112=2.78
rectangular pioints are(-1.12,2.78)
Thanks for checking
1.Find polar form of (-3,2)
r=sqrt of (-3)^2 + 2^2)=sqrt (13) = 3.61
tan^-1(2/-3) = 33.79
180-33.79 = 146.31degrees
polar points are (sqrt13,146.31degrees)
2. Rectangular form of (3,112degrees)
3cos112= (-1.12)
3sin112=2.78
rectangular pioints are(-1.12,2.78)
Thanks for checking
Answers
Answered by
Steve
Looks good to me.
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