Asked by ashley
A golfer takes two putts to get his ball into the hole once he is on the green. The first putt displaces the ball 6.90 m east, the second 7.70 m south. What displacement would have been needed to get the ball into the hole on the first putt?
Answers
Answered by
Henry
V1 = (6.90m,0 deg).
V2 = (7.7m,270 deg).
X = hor. = 6.90cos(0) + 7.7cos270,
X = 6.90 + 0 = 6.90m.
Y = ver. = 6.90sin(0) + 7.7sin270,
Y = 0 + (-7.7) = -7.7m.
tanA = Y / X = -7.7 / 6.9 = -1.1159,
A = -48.1 deg,CW.
A = -48.1 + 360 = 312 deg.,CCW.
D = X / cosA = 6.90 / cos312 = 10.3m @
312 deg.
V2 = (7.7m,270 deg).
X = hor. = 6.90cos(0) + 7.7cos270,
X = 6.90 + 0 = 6.90m.
Y = ver. = 6.90sin(0) + 7.7sin270,
Y = 0 + (-7.7) = -7.7m.
tanA = Y / X = -7.7 / 6.9 = -1.1159,
A = -48.1 deg,CW.
A = -48.1 + 360 = 312 deg.,CCW.
D = X / cosA = 6.90 / cos312 = 10.3m @
312 deg.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.