Asked by Rebecca
One zero of f(x)=x^3+4x^2+x+c is -3.
a) calculate the value of c.
b)calculate the other zeros.
a) calculate the value of c.
b)calculate the other zeros.
Answers
Answered by
Anonymous
Ummm, didn't MathMate just do one of these for you? Plug in -3 and evaluate to find c.
Answered by
Anonymous
Ummmmm, I needed help with the second part
Answered by
Steve
Divide by x+3 and see what you get:
x^3 + 4x^2 + x -6
= (x+3)(x^2 + x - 2)
= (x+3)(x+2)(x-1)
Got it now?
x^3 + 4x^2 + x -6
= (x+3)(x^2 + x - 2)
= (x+3)(x+2)(x-1)
Got it now?
Answered by
Confused
what about this question:
Determine the roots algebraically by factoring.
a) x^3-8x^2-3x+90=0
Determine the roots algebraically by factoring.
a) x^3-8x^2-3x+90=0
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.