Asked by hellow
I have this question:
A 71.7-mL solution of 0.182 M NaOH is titrated with 0.2086 M HC.
And I got the rest of the question of right...but for this one part.
4.) after addition of 50.0 mL of HCl
i keep on getting 12.95 but I'm wrong...can someone tell me what to do?
A 71.7-mL solution of 0.182 M NaOH is titrated with 0.2086 M HC.
And I got the rest of the question of right...but for this one part.
4.) after addition of 50.0 mL of HCl
i keep on getting 12.95 but I'm wrong...can someone tell me what to do?
Answers
Answered by
bobpursley
Volumebase*molaritybase=volumeacid*molarityacid
Volume acid= 71.7ml*.182M/.2086M
Volume acid= 71.7ml*.182M/.2086M
Answered by
hellow
...and what do I do withe 50?
Answered by
hellow
*with the
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