grams= Molarity*volumeinliters*molmass
= 4.73E-6*1*792.86 grams
The empirical formula for Brilliant Blie dye is C37 H34 N2 O9 S3 Na2, and the formula weight is 792.86 g/mol. How would you prepare a 4.73 X 10^-6 M solution of Brilliant Blue dye? How many grams of the dye do you need to add to a 1.00 L of water to make this solution?
I have no idea what this question is asking. Do you need to calculate a number or just explain what to do to create the dye? Thank you for your help because I am lost!!!
2 answers
I think the problem is asking for a detailed explanation of how to prepare 1 L of the soln including calculations.
You want a 4.73E-4M soln which means you want 4.73E-4 moles/L soln.
So you weigh the number of grams to obtain 4.73E-4 moles (moles = grams/molar mass), place that in a 1L volumetric flask, add enough water to dissolve all of the dye, then add additional water to the mark of the volumetric flask. Note that I did NOT (repeat NOT) say to add the grams of dye to 1 L water.
You want a 4.73E-4M soln which means you want 4.73E-4 moles/L soln.
So you weigh the number of grams to obtain 4.73E-4 moles (moles = grams/molar mass), place that in a 1L volumetric flask, add enough water to dissolve all of the dye, then add additional water to the mark of the volumetric flask. Note that I did NOT (repeat NOT) say to add the grams of dye to 1 L water.
3 answers