Asked by unknown
If the twelfth term of an arithmetic sequence is 58 and the constant difference is 2, what is the first term of the sequence?
Answers
Answered by
Reiny
easy.
d = 2
12 term is 58 ---> a+11d = 58
a+22=58
a = 36
d = 2
12 term is 58 ---> a+11d = 58
a+22=58
a = 36
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