Asked by tara
write the equation of the line tangent to the curve y= 3x^3- 2x at the point where x=2
Answers
Answered by
bobpursley
y'= 9x^2-2 which is the slope,
y'=34 at x=2
y= mx+b
y=34x+b
now at x=2, y= 3*8-4=22
22=34*2+b solve for b, and you have the equation of the tangent.
y'=34 at x=2
y= mx+b
y=34x+b
now at x=2, y= 3*8-4=22
22=34*2+b solve for b, and you have the equation of the tangent.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.