Asked by Mah
A Pratt and whitney PW4000 turbofan engine is able to provide a maximum thrust of 2.49 x 100000 N.A Boeing 747-400 airliner has four of these engines. If its mass is 2.72 x 100000 kg, what is its acceleration?
Answers
Answered by
drwls
That will depend upon the aerodynamic drag, which was not provided.
If the drag were zero, the acceleration would be F/m =
4*2.49*10^5/2.72*10^5 m/s^2
= 3.67 m/s^2
Zero drag is a fair approximation at low speeds, e.g. takeoff.
If the drag were zero, the acceleration would be F/m =
4*2.49*10^5/2.72*10^5 m/s^2
= 3.67 m/s^2
Zero drag is a fair approximation at low speeds, e.g. takeoff.
Answered by
shanjeed
That will depend upon the aerodynamic drag, which was not provided.
If the drag were zero, the acceleration would be F/m =
4*2.49*10^5/2.72*10^5 m/s^2
= 3.67 m/s^2
Zero drag is a fair approximation at low speeds, e.g. takeoff.
If the drag were zero, the acceleration would be F/m =
4*2.49*10^5/2.72*10^5 m/s^2
= 3.67 m/s^2
Zero drag is a fair approximation at low speeds, e.g. takeoff.
There are no AI answers yet. The ability to request AI answers is coming soon!