Asked by Mohammad
                Illustrate in diagram a force 150N is inclined a 50 to the horizontal direction find it component in the horizontal
            
            
        Answers
                    Answered by
            drwls
            
    We do not have the tools to provide diagrams. The x-component of the vector you have described would be 
150 cos50 = 96.4 N
    
150 cos50 = 96.4 N
                    Answered by
            Anonymous
            
    Fx equal 150cos50 degree equal to the 96.4 n.
    
                    Answered by
            marvelous RCA
            
    150cos50=96.4n 
    
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